Optimal. Leaf size=138 \[ -\frac{a^3 \sin ^3(c+d x)}{d}-\frac{2 a^3 \sin (c+d x)}{d}+\frac{3 a^3 \tan (c+d x)}{d}+\frac{3 a^3 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{a^3 \sin (c+d x) \cos ^3(c+d x)}{4 d}+\frac{7 a^3 \sin (c+d x) \cos (c+d x)}{8 d}+\frac{a^3 \tan (c+d x) \sec (c+d x)}{2 d}-\frac{33 a^3 x}{8} \]
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Rubi [A] time = 0.227665, antiderivative size = 138, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 9, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.429, Rules used = {3872, 2872, 2637, 2635, 8, 2633, 3770, 3767, 3768} \[ -\frac{a^3 \sin ^3(c+d x)}{d}-\frac{2 a^3 \sin (c+d x)}{d}+\frac{3 a^3 \tan (c+d x)}{d}+\frac{3 a^3 \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac{a^3 \sin (c+d x) \cos ^3(c+d x)}{4 d}+\frac{7 a^3 \sin (c+d x) \cos (c+d x)}{8 d}+\frac{a^3 \tan (c+d x) \sec (c+d x)}{2 d}-\frac{33 a^3 x}{8} \]
Antiderivative was successfully verified.
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Rule 3872
Rule 2872
Rule 2637
Rule 2635
Rule 8
Rule 2633
Rule 3770
Rule 3767
Rule 3768
Rubi steps
\begin{align*} \int (a+a \sec (c+d x))^3 \sin ^4(c+d x) \, dx &=-\int (-a-a \cos (c+d x))^3 \sin (c+d x) \tan ^3(c+d x) \, dx\\ &=-\frac{\int \left (5 a^7+5 a^7 \cos (c+d x)-a^7 \cos ^2(c+d x)-3 a^7 \cos ^3(c+d x)-a^7 \cos ^4(c+d x)-a^7 \sec (c+d x)-3 a^7 \sec ^2(c+d x)-a^7 \sec ^3(c+d x)\right ) \, dx}{a^4}\\ &=-5 a^3 x+a^3 \int \cos ^2(c+d x) \, dx+a^3 \int \cos ^4(c+d x) \, dx+a^3 \int \sec (c+d x) \, dx+a^3 \int \sec ^3(c+d x) \, dx+\left (3 a^3\right ) \int \cos ^3(c+d x) \, dx+\left (3 a^3\right ) \int \sec ^2(c+d x) \, dx-\left (5 a^3\right ) \int \cos (c+d x) \, dx\\ &=-5 a^3 x+\frac{a^3 \tanh ^{-1}(\sin (c+d x))}{d}-\frac{5 a^3 \sin (c+d x)}{d}+\frac{a^3 \cos (c+d x) \sin (c+d x)}{2 d}+\frac{a^3 \cos ^3(c+d x) \sin (c+d x)}{4 d}+\frac{a^3 \sec (c+d x) \tan (c+d x)}{2 d}+\frac{1}{2} a^3 \int 1 \, dx+\frac{1}{2} a^3 \int \sec (c+d x) \, dx+\frac{1}{4} \left (3 a^3\right ) \int \cos ^2(c+d x) \, dx-\frac{\left (3 a^3\right ) \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{d}-\frac{\left (3 a^3\right ) \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin (c+d x)\right )}{d}\\ &=-\frac{9 a^3 x}{2}+\frac{3 a^3 \tanh ^{-1}(\sin (c+d x))}{2 d}-\frac{2 a^3 \sin (c+d x)}{d}+\frac{7 a^3 \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^3 \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{a^3 \sin ^3(c+d x)}{d}+\frac{3 a^3 \tan (c+d x)}{d}+\frac{a^3 \sec (c+d x) \tan (c+d x)}{2 d}+\frac{1}{8} \left (3 a^3\right ) \int 1 \, dx\\ &=-\frac{33 a^3 x}{8}+\frac{3 a^3 \tanh ^{-1}(\sin (c+d x))}{2 d}-\frac{2 a^3 \sin (c+d x)}{d}+\frac{7 a^3 \cos (c+d x) \sin (c+d x)}{8 d}+\frac{a^3 \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{a^3 \sin ^3(c+d x)}{d}+\frac{3 a^3 \tan (c+d x)}{d}+\frac{a^3 \sec (c+d x) \tan (c+d x)}{2 d}\\ \end{align*}
Mathematica [A] time = 0.450713, size = 114, normalized size = 0.83 \[ \frac{a^3 \sec ^2(c+d x) \left (-16 \sin (c+d x)+225 \sin (2 (c+d x))-72 \sin (3 (c+d x))+18 \sin (4 (c+d x))+8 \sin (5 (c+d x))+\sin (6 (c+d x))-264 (c+d x) \cos (2 (c+d x))+192 \cos ^2(c+d x) \tanh ^{-1}(\sin (c+d x))-264 c-264 d x\right )}{128 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.044, size = 159, normalized size = 1.2 \begin{align*}{\frac{11\,{a}^{3}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{4\,d}}+{\frac{33\,{a}^{3}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{8\,d}}-{\frac{33\,{a}^{3}x}{8}}-{\frac{33\,{a}^{3}c}{8\,d}}-{\frac{{a}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{2\,d}}+{\frac{3\,{a}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}-{\frac{3\,{a}^{3}\sin \left ( dx+c \right ) }{2\,d}}+3\,{\frac{{a}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{d\cos \left ( dx+c \right ) }}+{\frac{{a}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.5212, size = 246, normalized size = 1.78 \begin{align*} -\frac{16 \,{\left (2 \, \sin \left (d x + c\right )^{3} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right ) + 6 \, \sin \left (d x + c\right )\right )} a^{3} -{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) - 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} a^{3} + 48 \,{\left (3 \, d x + 3 \, c - \frac{\tan \left (d x + c\right )}{\tan \left (d x + c\right )^{2} + 1} - 2 \, \tan \left (d x + c\right )\right )} a^{3} + 8 \, a^{3}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} + 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, \log \left (\sin \left (d x + c\right ) - 1\right ) - 4 \, \sin \left (d x + c\right )\right )}}{32 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.90757, size = 381, normalized size = 2.76 \begin{align*} -\frac{33 \, a^{3} d x \cos \left (d x + c\right )^{2} - 6 \, a^{3} \cos \left (d x + c\right )^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) + 6 \, a^{3} \cos \left (d x + c\right )^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) -{\left (2 \, a^{3} \cos \left (d x + c\right )^{5} + 8 \, a^{3} \cos \left (d x + c\right )^{4} + 7 \, a^{3} \cos \left (d x + c\right )^{3} - 24 \, a^{3} \cos \left (d x + c\right )^{2} + 24 \, a^{3} \cos \left (d x + c\right ) + 4 \, a^{3}\right )} \sin \left (d x + c\right )}{8 \, d \cos \left (d x + c\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.3166, size = 243, normalized size = 1.76 \begin{align*} -\frac{33 \,{\left (d x + c\right )} a^{3} - 12 \, a^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) + 12 \, a^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) + \frac{8 \,{\left (5 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 7 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{2}} + \frac{2 \,{\left (25 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 81 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 79 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 7 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{4}}}{8 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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